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x^2+11^2=60^2
We move all terms to the left:
x^2+11^2-(60^2)=0
We add all the numbers together, and all the variables
x^2-3479=0
a = 1; b = 0; c = -3479;
Δ = b2-4ac
Δ = 02-4·1·(-3479)
Δ = 13916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13916}=\sqrt{196*71}=\sqrt{196}*\sqrt{71}=14\sqrt{71}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{71}}{2*1}=\frac{0-14\sqrt{71}}{2} =-\frac{14\sqrt{71}}{2} =-7\sqrt{71} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{71}}{2*1}=\frac{0+14\sqrt{71}}{2} =\frac{14\sqrt{71}}{2} =7\sqrt{71} $
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